Integrand size = 14, antiderivative size = 14 \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\text {Int}\left (\frac {1}{x (a+a \cosh (x))^{3/2}},x\right ) \]
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Not integrable
Time = 0.07 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx \\ \end{align*}
Not integrable
Time = 8.83 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.14 \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx \]
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Not integrable
Time = 0.03 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.86
\[\int \frac {1}{x \left (a +a \cosh \left (x \right )\right )^{\frac {3}{2}}}d x\]
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Not integrable
Time = 0.24 (sec) , antiderivative size = 36, normalized size of antiderivative = 2.57 \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\int { \frac {1}{{\left (a \cosh \left (x\right ) + a\right )}^{\frac {3}{2}} x} \,d x } \]
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Not integrable
Time = 9.09 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\int \frac {1}{x \left (a \left (\cosh {\left (x \right )} + 1\right )\right )^{\frac {3}{2}}}\, dx \]
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Not integrable
Time = 0.35 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\int { \frac {1}{{\left (a \cosh \left (x\right ) + a\right )}^{\frac {3}{2}} x} \,d x } \]
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Not integrable
Time = 0.55 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\int { \frac {1}{{\left (a \cosh \left (x\right ) + a\right )}^{\frac {3}{2}} x} \,d x } \]
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Not integrable
Time = 1.84 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x (a+a \cosh (x))^{3/2}} \, dx=\int \frac {1}{x\,{\left (a+a\,\mathrm {cosh}\left (x\right )\right )}^{3/2}} \,d x \]
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